Answer:
It's the PURPULE one
Step-by-step explanation:
BTW can u pls help me in my question thanks
So we need to find the common multiples of 6 and 12. Which are basically the multiples of 12, since 6 is always divisible to 12. So (12, 24, 36, 48, 60, 72, 84, 96, 108) Since it is a factor of 108, we stop at 108 (since a number greater than 108 can't be a factor of 108)
Now we find the factors of 108
108=<span>1,2,3,4,6,9,12,18,27,36,54,108
The numbers in both lists are 36 and 108 but since Micah is thinking of a 2-digit number, the number she is thinking of is 36.</span>
The total number of pieces of chalk in the classroom will be the number of pieces in the 4 boxes in addition to the six individual pieces.
The average box of chalk holds 12 pieces of chalk
This means that 4 boxes have 12*4 = 48 pieces
Total number of pieces = 48 + 6 = 54 pieces of chalk
Domain: x values
Range: y values
The relation would need to have (2, y) and (4, y). And also (x, 2) and (x, 8)
See which ones match
Solution: B
Answer:
-1 is your answer for this mate
