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2 years ago

11

Triangle QRS is similar to triangle TUV. Write the equation, in slope-intercept form, of the side of triangle QRS that is parall

el to segment UV. You must show all work to receive credit.

1 answer:

trasher [3.6K]2 years ago

6 0

Answer:

The equation of the side of triangle QRS that is parallel to segment UV is:

y = x + 9

Step-by-step explanation:

I attached a pic with the procedure to find the answer. Hope it helps, good luck!

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agasfer [191]

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You can call this number "zero point zero zero three."
Since the 3 is in the thousandths place, this number can also be called "three thousandths."
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"three thousandths" means 3 out of 1000.
The ratio is 3:1000 or 3/1000.

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2 years ago

If a package of corn chips weighs 1.2 ounces what is the weight in ounces of 48 packages ?

Naya [18.7K]

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3 years ago

Read 2 more answers

Paige used 1 1/2 cups of flour and 1/4 of butter to make 12 muffins. How much flour and butter would Paige need for 18 muffins?

maks197457 [2]

Answer:

3/4 cup

Step-by-step explanation:

12 divided by 2 is 6

18 - 12 = 6

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2 years ago

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Write the factors of a2-b2.

nignag [31]

Answer:
(a + b) and (a - b)

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3 years ago

Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3

Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

$f(x)=x^4-2ax^3+ax^2- x+k$

and

$f(-1)=3$

Answer:

$k = -2$ and $a=1$

Step-by-step explanation:

Given

$f(x)=x^4-2ax^3+ax^2- x+k$

$Factor:\ x - 4$

$f(-1)=3$

Required

Find a and k

For $f(-1)=3$

Substitute -1 for x

$f(x)=x^4-2ax^3+ax^2- x+k$

$f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k$

$f(-1) = 1 - 2a *-1 + a*1 +1 + k$

$f(-1) = 1 +2a + a +1 + k$

$f(-1) = 2 +3a + k$

Substitute 3 for f(-1)

$3 = 2 +3a + k$

Collect Like Terms

$3 - 2 = 3a + k$

$1 = 3a + k$

Also:

If $x - 2$ is a factor, then

$f(2) = 0$

Substitute 2 for x and 0 for f(x)

$f(x)=x^4-2ax^3+ax^2- x+k$

$0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k$

$0 = 16 - 2a * 8 + a * 4 - 2 + k$

$0 = 16 - 16a + 4a - 2 + k$

$0 = 16 - 12a - 2 + k$

Collect Like Terms

$2 - 16 = - 12a + k$

$-14 = k - 12a$

$k = 12a - 14$

Substitute 12a - 14 for k in $1 = 3a + k$

$1 = 3a + 12a - 14$

$1 = 15a - 14$

Collect Like Terms

$15a = 1 + 14$

$15a = 15$

Solve for a

$a = \frac{15}{15}$

$a=1$

Substitute 1 for a in $k = 12a - 14$

$k = 12 * 1 - 14$

$k = 12 - 14$

$k = -2$

3 0

2 years ago