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3 years ago

Subtract 19/12 - 3/4

Mathematics

2 answers:

IRISSAK [1]3 years ago

8 0

Answer:

$\frac{19}{12} - \frac{3}{4}=\frac{5}{6}$

Step-by-step explanation:

$\frac{19}{12} - \frac{3}{4}$

$= \frac{19 \times 4}{12 \times 4} - \frac{3 \times 12}{4 \times 12}$

$= \frac{76}{48} - \frac{36}{48}$

$= \frac{76 - 36}{48}$

$= \frac{40}{48}$

$= \frac{40 \div 8}{48 \div 8}$

$= \frac{5}{6}$

AfilCa [17]3 years ago

4 0

<h2>◇Answer : </h2>

$\rm \frac{19}{12} - \frac{3}{4} = \frac{9}{12} - \frac{9}{12} = \frac{9 - 9}{12} = \frac{0}{12} = \bf0 \: \: (done.)$

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An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object

Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

$1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2 + \frac{1}{2} at^2\\3) v = v_0 + at$

What do we already know?

$v_0 = 29.4 ms^-1$
The launch is straight up
$a = -9.81 ms^-2$ this is the gravitational acceleration $g$

$s_0 = 0 m$ , since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, $v = 0 ms^-2$

$v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m$

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

$s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2$

this is the equation of the whole trajectory that object makes.

and if you solve this by making $s = 0$ , you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

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3 years ago

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2 years ago

The distribution of the number of occurrences of the letter t on the pages of a book is found to be a normal distribution with a

Leno4ka [110]

The distribution of the number of occurrences of the letter t on the pages of a book is found to be a normal distribution with a mean of 44 and a standard deviation of 18. If there are 500 pages in the book, which sentence most closely summarizes the data?

A. The letter t occurs less than 26 times on approximately 170 of these pages.

B. The letter t occurs less than 26 times on approximately 15 of these pages.

C. The letter t occurs more than 26 times on approximately 420 of these pages.

D. The letter t occurs more than 26 times on approximately 80 of these pages.

.Answer:
mean = 44 
sd = 18 
that means that "26" is 1 s.d. down, or at the 16th %ile 

so, there is a .16 chance that "t" will occur less than 26 times on any single page. 
consequently, there is a .84 chance that it will occur more than 26 times on any single page. 

Using that information, and knowing that 16% of 500 is 80, and 84% of 500 is 420, can you see where "C" is correct?

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4 years ago

Read 2 more answers

Find the measure of angle X in the figure below

alexandr1967 [171]

Answer:

50 degrees

Step-by-step explanation:

65 times 2=130

180-130=50

7 0

3 years ago

Please help (the question is in the attached image)

Alex73 [517]

Answer:

a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm

sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.

than AT=BT

3x+6=42-x

3x+x=42-6

x=36/4=9

AT=3×9+6=27+6=33

since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.

EH=GH

5y+10=28-y

6y=28-10

y=18/6=3

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3 years ago