3 years ago

Help me please ;-;

Mathematics

2 answers:

antoniya [11.8K]3 years ago

8 0

Answer:

-14

Step-by-step explanation:

Alexeev081 [22]3 years ago

4 0

Answer:

Step-by-step explanation:

y=4x - 2 x= -3

y=4(-3) - 2

y= -12 - 2

y= -14

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Consider the expression below

brilliants [131]

This one is my real answer 5{10+3]=40 The other one you can use for extra this one 5{10+25]=35

4 0

3 years ago

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

3 years ago

If cheese is 4.40 per kilogram, what should I pay for 200 grams

N76 [4]

200 grams is is 0.2 kilograms, so you would pay $0.88 because 4.40x0.2=0.88

6 0

3 years ago

Read 2 more answers

⦁ To the nearest tenth, find the perimeter of ∆ABC with vertices A(2,4), B(-2,1) and C(2,1). Show your work.

Colt1911 [192]

We need the length of the sides.
AB=√(2-(-2))²+(4-1)²=√16+9=√25=5; BC=√4²+0=4; CA=√0+9=3. AB+BC+CA=5+4+3=12.

5 0

3 years ago

Item 14

dsp73

Answer:

13/21

Step-by-step explanation:

5 0

2 years ago