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valentinak56 [21]
2 years ago
10

3x+4y+6z=15Solve for x.​

Mathematics
2 answers:
aalyn [17]2 years ago
3 0

Answer:

<h2> </h2><h2>x = 5 -  \frac{4}{3} y - 2z</h2>

Step-by-step explanation:

<h3><u>Question</u><u>:</u><u>-</u></h3>
  • To solve for x

<h3><u>Equation</u><u>:</u><u>-</u></h3>
  • 3x + 4y + 6z = 15

<h3><u>Solution</u><u>:</u><u>-</u></h3>

=> 3x + 4y + 6z = 15

  • <em>[</em><em>On</em><em> </em><em>subtracting</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>4y</em><em>]</em>

=> 3x + 4y + 6z - 4y = 15 - 4y

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=> 3x + 6z = 15 - 4y

  • <em>[</em><em>On</em><em> </em><em>subtracting</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>6z</em><em>]</em>

=> 3x + 6z - 6z = 15 - 4y - 6z

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=> 3x = 15 - 4y - 6z

  • <em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>3</em><em>]</em>

=  >  \frac{3x}{3}  =  \frac{15 - 4y - 6z}{3}

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=  > x = 5 -  \frac{4}{3} y - 2z \: (ans)

puteri [66]2 years ago
3 0

\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}

\huge\bold\orange{QUESTIONS:}

  • 3x+4y+6z=15 Solve for x.

\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}

\huge\bold\orange{ANSWER:}

x = 5 -  \frac{4}{3} y - 2z

\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}

\huge\bold\orange{SOLUTION:}

3  \orange{+ 4y + 6z = 15}

Move the variables to the right-hand side and change their signs.

3x = 15 \orange{ - 4 - 6z}

Divide both sides of the equation by 3

\orange{3x = 15 - 4 - 6z}

↓

\orange{x = 5 -  \frac{4}{3} y - 2z}

The x-intercepts of 3x+4y+6z=15 is

x = 5 -  \frac{4}{3} y - 2z

\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}

#CarryOnlearning

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