A rational number is a real number such as 5 or .25. An irrational number is a non realistic number such as pi
Answer:97 rods
Step-by-step explanation:
The number of steel rods for 95% confidence level
E=3
Substituting values
Thus 97 rods is tested
No because the 3 is the tens place. So its supposed to 3 ten blocks
You must drive more than 40 miles to make option A the cheaper plan
<em><u>Solution:</u></em>
Two payment options to rent a car
Let "x" be the number of miles driven in one day
<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>
25 cents is equal to 0.25 dollars
OPTION A : 20 + 0.25x
<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>
50 cents equal to 0.50 dollars
Option B: 10 + 0.50x
<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>
For option A to be cheaper, Option A must be less than option B
Option A < Option B
Solve the inequality
Add -0.50x on both sides
Add - 20 on both sides,
Divide both sides by 0.25
Thus you must drive more than 40 miles to make option A the cheaper plan
Each division set gives the outcome of the operation 1.45 ÷ 5 which is 0.29.
- The number of hundredths in each division set is <u>D. 9</u>
Reasons:
The given Hunter's model consists of the following
One 10 × 10 number block
Four sets of a column of 10 cubes
Five individual cube pieces
Therefore;
In 1.45, we have;
1 unit
4 tenths
5 hundredths
Which gives;
Each single cube can be used to represent a hundredth in 0.05
One cube = 0.01
Each set of 10 cubes represents a tenth in 0.4
Each block of 10 by 10 can be used to represent the unit; 1
Dividing each of the 10 × 10 can be divided to sets of 20 blocks with a value of 0.2 each
The 4 sets of 10s can be divided by 5 to give sets of 8 with a value of 0.08
The 5 cubes divided 5 gives five cubes with each cube having a value of 0.01.
Therefore;
The value of each division set is 0.2 + 0.08 + 0.01 = 0.29
The number of hundredths in 0.29 = 9
The number of hundredths in each division set is therefore; <u>D. 9</u>
Learn more about number place value here:
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