Answer:
The cost of production and using more efficient resources
The Winter Olympics are held every 4 years.
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
The distance between the campsite and the rest area is 9 miles.
The given parameters:
- <em>Initial speed of the campers, u = 4.5 mph</em>
- <em>Final speed of the campers, v = 4 mph</em>
<em />
Let the time of motion from the campsite to rest area = t (hours)
Time for return trip = t hours + 15 mins
= (t + 0.25) hours
Let the distance between the campsite and rest area = d
d = 4.5t
d = 4(t + 0.25)
4.5t = 4(t + 0.25)
4.5t = 4t + 1
4.5t - 4t = 1
0.5t = 1
t = 2 hours
The distance between the campsite and the rest area is calculated as follows;
d = 4.5t
d = 4.5 x 2
d = 9 miles
Thus, the distance between the campsite and the rest area is 9 miles.
Learn more about distance and speed here: brainly.com/question/2854969
