Answer:
C
Step-by-step explanation:
C
the answer is 6.9.
When you divide a negative by a negative it is a positive
Answer:
the y intercept is 5 because the line passes through 5 on the y axis. Now to find the slope, pick two points where the line hits directly on the corner of the grid squares. pIck 2 of those and count the squares up till you are lined up with your other point then count over and get another number. Put the number going up over the number going down like x/y and you'll have your answer. ( simplify it if you can.(-2,3) and (0,5) are a good place to start. The answer should be 2/3. Hope this helped and God bless!
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
It should be 5/13 because the opposite angle from D is 12, which you would use if you are looking for sine. But, since you are looking for cosine, it is adjacent over hypotenuse. Therefore leaving you with 5/13, since your hypotenuse is always your longest side and the adjacent is the other side from the one opposite of the angle.
