Answers:
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5
Part C: See below.

Explanations:
Part A:
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms:
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8
12y² + 10y – 21

Part B:
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21
Create an algebraic expression:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y² – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26
– 10y – 10y
– 21 + d = 4y³ + 6y² + 6y – 26
+ 21 + 21
d = 4y³ + 6y² + 6y – 5

Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.

7 0

3 years ago

Please help, this makes no sense to me

aev [14]

Answer:

7/11

Step-by-step explanation:

Let X equal the decimal number

Equation 1:

X=0.63¯¯¯¯¯

With 2 digits in the repeating decimal group,

create a second equation by multiplying

both sides by 102 = 100

Equation 2:

100X=63.63¯¯¯¯¯

Subtract equation (1) from equation (2)

100XX99X===63.63...0.63...63

We get

99X=63

Solve for X

X=6399

Find the Greatest Common Factor (GCF) of 63 and 99, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 9,

63÷999÷9=711

Therefore

X=711

In conclusion,

0.63¯¯¯¯¯=711

used

https://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php

6 0

3 years ago