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MrMuchimi
3 years ago
10

29. The two quadrilaterals are similar Find

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

Answer: C 78 units

Step-by-step explanation:

If two quadrilaterals are similar, that means that they must have a scale factor that makes one of the figures bigger proportionally, so we can find the scale factor by taking to corresponding sides and dividing the bigger one over the smaller one...

YZ/QS = 13/4 = 3.25 (scale factor)

Now we can multiply the smaller sides by 3.25 to find any sides that we don't know the size of (for the bigger quadrilateral).

PQ * 3.25 = 9 x 3.25 = 29.25 (XY)

PR * 3.25 = 3 x 3.25 = 9.75 (XW)

Add the lengths together to get the perimeter...

XY + XW + WZ + YZ = 29.25 + 9.75 + 26 + 13 = 78 units

*remember to use scale factor to find the lengths or measurements for proportionally bigger figures... :D

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BARSIC [14]

Option C:

The perimeter of the rhombus is 100 inches.

Solution:

AC = 30 inches, BD = 40 inches

In rhombus, diagonals bisect each other at right angles.

AE = CE = 15 inches

BE = ED = 20 inches

In ΔAED, ∠E = 90°

Using Pythagorean theorem,

AD^2=AE^2 +ED^2

AD^2=15^2 +20^2

AD^2=225+400

AD^2=625

AD^2=25^2

Taking square root on both sides, we get

AD = 25 inches

In rhombus, all sides are equal in length.

AD = DC = CB = BA = 25 inches.

Perimeter = AD + DC + CB + BA

                 = 25 + 25 + 25 + 25

                 = 100 inches

The perimeter of the rhombus is 100 inches.

Option C is the correct answer.

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