A) Both terms contain x, so they can be combined. -25 + 36 = 11 therefore -25x + 36x = 11x
B) 7s and 3s both contain s, so they can be combined, but the 3 cannot be combined with them as it does not contain an s. 7 - 3 = 4 therefore 7s - 3s = 4s. The 3 stays on its own as it cannot be combined, therefore the answer is 4s + 3
C) 12x and 2x contain x, so they can be combined, but the 11 cannot be combined with them as it does not contain an x. 12 - 2 = 10 therefore 12x - 2x = 10x. The 11 stays on its own as it cannot be combined, therefore the answer is 10x - 11
Answer:
Step-by-step explanation:
BC/AB = DE/AD
1/2 = x/(2+1)
x = 1.5
The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
Answer:
You can use the ASA Postulate to prove the Angle-Angle-Side Congruence Theorem. A flow proof is shown below. If two angles and a nonincluded side of one triangle are congruent to two angles and the corresponding nonincluded side of another triangle, then the triangles are congruent.
Step-by-step explanation:
Hope it helps! Correct me if I am wrong!
I'm sure about my answer!
If you dont mind can you please mark me as brainlest?
Its ok if you don't want to!
