Answer:
It's a he
Step-by-step explanation:
It is a man living in Libya, who sends messages through ha.cked people's accounts.
Answer:
The Answer is that Senior Citizen Tickets cost: $4 and Child tickets cost: $7.
Step-by-step explanation:
Let s = the cost of senior citizen tickets
Let c = the cost of child tickets
The number of tickets sold for each type added together equals the sales for each day. Equations below:
Day 1
3s + 9c = $75
Solve for s:
3s = 75 - 9c
s = 25 - 3c
Day 2
8s + 5c = $67
By substitution:
8(25 - 3c) + 5c = 67
200 - 24c + 5c = 67
-19c = -133
c = -133 / -19 = $7 cost for child tickets.
Solve for s:
s = 25 - 3c
s = 25 - 3(7)
s = 25 - 21 = $4 cost for senior citizen tickets.
Proofs:
Day 1
3s + 9c = $75
3(4) + 9(7) = 75
12 + 63 = 75
75 = 75
Day 2
8s + 5c = $67
8(4) + 5(7) = 67
32 + 35 = 67
67 = 67
Answer: Marc still owes $175
Step-by-step explanation:
Let x represent the cost of the rug.
Marc ordered a rug and gave a deposit of 30% of the cost and will pay the rest when the rug is delivered. This means that the amount of money that he deposited
for the rug is
30/100 × x = 0.3 × x = 0.3x
If the deposit was $75, it means that
0.3x = 75
x = 75/0.3 = 250
The cost of the rug is $250
The amount that Marc still owes would be
250 - 75 = $175
Answer:
see explanation
Step-by-step explanation:
The roots are the points on the x- axis where the graph crosses
The roots are (- 3, 0 ) or (1, 0 )
The turning point is at (- 1, - 4 ) ← where the graph turns
Answer:
P(Y ≥ 15) = 0.763
Step-by-step explanation:
Given that:
Mean =135
standard deviation = 12
sample size n = 50
sample mean
= 140
Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses
Then,

The probability that X is greater than 140 is :
P(X>140) = 1 - P(X ≤ 140)



From z tables,


Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140
Then;


∴
P(Y ≥ 15) = 1- P(Y< 15)
P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y ≥ 15) = 0.763