Question

Need help please and thank you.​

Answer 1

Answer:

$log_4(\frac{1}{64})=-3$

Step-by-step explanation:

$log_b(b^x)=x$

• Let b = base and x = the exponent

    Looking at the equation given, we know the base (the number with the exponent) is 4, the exponent itself is -3, and the value is 1/64. Based on this information, fill in the formula and simplify any values.

$log_4(4^{-3})=-3\\log_4(\frac{1}{64})=-3$

Therefore, the logarithmic form is $log_4(\frac{1}{64})=-3$.