2a^3-4a^2+5a+3
Explanation:
For standard form you always start with the one that has the biggest exponent to the least one
The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.
Step-by-step explanation:
The given is,
The sum of two numbers is 21
The second number is six times the first number
Step:1
Let, m - First number
n - Second number
Step:2
From given,
n - 6m ( The second number is six times the first number )
Equation becomes,
Sum = m + n
Where,
21 = m + ( 6m )
21 = 7m
m = 3
Substitute m value n becomes,
n = 6m
= (6 × 3)
n = 18
Result:
The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.
7x+y=7
in a slope intercept form
y=-7x+7
where,
slope(m)=-7 & c=7
