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Zepler [3.9K]
2 years ago
13

What is the value of the expression below when z=3?

Mathematics
1 answer:
sashaice [31]2 years ago
5 0

Answer:

82

Step-by-step explanation:

10z^2 - 2z - 2 =

10(3)^2 - 2(3) - 2 =

10(9) - 2(3) - 2 =

90 - 6 - 2 = 82

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Tanya [424]
If the sides are close together, its acute. 

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Answer: the answer is option c


Step-by-step explanation:


7 0
3 years ago
A triangle has vertices at (-2,-3),(4, -3), and (3,5). What is the area of the triangle?
Bezzdna [24]

Answer:

this triangle is ABC with A(-2 ; -3), B(4; - 3) and C(3;5)

=> AB=\sqrt{(4-(-2))^{2}+\sqrt{(-3 -(-3))^{2} }  }=\sqrt{6^{2} }=6\\\\AC=\sqrt{(3-(-2))^{2}+(5-(-3))^{2}  }=\sqrt{5^{2}+8^{2}  }=\sqrt{89}\\\\BC =\sqrt{1^{2}+8^{2}  }=\sqrt{65}

using Heron theorem, we have:

S=\sqrt{p(p-AB)(p-AC)(p-BC)}\\\\S=\sqrt{(\frac{6+\sqrt{89}+\sqrt{65} }{2})(\frac{\sqrt{89}+\sqrt{65}-6  }{2} )(\frac{6+\sqrt{65}-\sqrt{89}  }{2})(\frac{6+\sqrt{89}-\sqrt{65}  }{2})   }\\\\S=24  \\\\

with S is the area of the triangle

       p=\frac{AB+AC+BC}{2}=\frac{6+\sqrt{89}+\sqrt{65}  }{2}

Step-by-step explanation:

5 0
3 years ago
Graph DEF and its image when you translate DEF using vector
adelina 88 [10]

Answer:

The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)

Now, translation by vector (6, 0)

D (2, 5)=D'(2+6, 5+0)=D'(8, 5)

E (6, 3)=E'(6+6, 3+0)=E'(12, 3)

F (4, 0)=F'(4+6, 0+0)=F'(10,0)

Now, we have to label the coordinate of the triangle or to get image of triangle after translation.

Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

4 0
3 years ago
18
IrinaK [193]
Answer: y = 1/5(x-1) -2

Point slope form looks like this:
y = m(x-x1) + y1

m = 1/5
x1 = 1
y1 = -2

Plug all of this into the formula and you should have your equation in point slope form.
6 0
2 years ago
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