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3 years ago

F(x)=x^2-3x-12 g(x)=-x-12 Find (f o g)(-8)

Mathematics

1 answer:

sashaice [31]3 years ago

8 0

Answer:

830

Step-by-step explanation:

Just add the numbers up and then divide

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PLS HELP

Fiesta28 [93]

Answer:

1. 1/3 x 2/2 = 1/3

2. 1/4 x 5/5 = 1/4

3. 1/6 x 4/4 = 1/6

4. 9/8 x 3/4 = (9x3)/(8x4) = 27/32

4. 4/5 x 2/2 = 4/5

Step-by-step explanation:

n/n = 1

7 0

3 years ago

Help me please thanks

kow [346]

Correct answer:
First reflect across the y-axis, then rotate 90 degrees clockwise about point K, then shift 3 units down.

6 0

3 years ago

Which point is located at -0.135? <br> A<br> B <br> C or <br> D

Sergeu [11.5K]

D as you can see on the number line d is 1/3 of the way to -2

6 0

3 years ago

Martha drew a pair of intersecting non-perpendicular lines, I and m. She numbered one pair of vertical angles <1 and <2, a

RUDIKE [14]

Answer:

D. Because <1 and <2 are each supplementary to <3, they are therefore congruent

Step-by-step explanation:

A. m<1 + m<2 + m<3 + m<4 = 360

Incorrect in terms of the proof

B. The sum of the measures of angles of a triangle is 180°

Not relevant

C. The measure of all right is 90°

Not relevant

D. Because <1 and <2 are each supplementary to <3, they are therefore congruent

Correct

8 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

4 years ago