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1 year ago

11

(√x-4/x-2√x+3/√x-2)

7D%7B%E2%88%9Ax%20-2%7D" id="TexFormula1" title="\frac{(√x-4) }{x-2√x} + \frac{3}{√x -2}" alt="\frac{(√x-4) }{x-2√x} + \frac{3}{√x -2}" align="absmiddle" class="latex-formula">

1 answer:

charle [14.2K]1 year ago

5 0

Answer: Down there there is an image with the correct answer and step by step

I hope that it helps you!

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Function 1 is defined by the equation y=-1/4r-5<br> Function 2

steposvetlana [31]

Step-by-step explanation:

as just answered in the other question, the y-intercept is simply the y-value, when x=0.

it is -5 for function 1.

and function 2 clearly crosses the y-axis at y = -7, which is the y-intercept.

as -5 is greater than -7, function 1 had the greater y- intercept.

3 0

1 year ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

8 months ago

The length of an edge of a cube is 9 centimeters. What is the volume of the cube?

KATRIN_1 [288]

Answer:

729

Step-by-step explanation:

Volume of cube=a^3

Volume of cube=9^3=729

3 0

2 years ago

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Olegator [25]

Answer:

B

Step-by-step explanation:

4 0

2 years ago

E^x = 25 <br><br> ...................

anzhelika [568]

X is equal to about 3.218876

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2 years ago

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