2/7 ( k+5/8) = 2 and 2/7
2/7 (k+5/8) = 16/7 |multiply by 7
2(k+5/8) = 16 |divide by 2
k+5/8 = 8 |subtract 5/8
k=8-5/8 = 7 and 3/8 = 27/8 = 7.375
Answer:
Ivan’s range: 2,640 = 2.64 x 10^3 ft
Winnies
range: (2.5)5280 = 13200 = 1.32 x 10^4 ft
Winnies WiFi has the greater range
The displaced volume of the water, because of the submersion of the object, is equal to the volume of the object.
So to find the volume of the object we calculate the difference in volume of water:
33.1-25.1 = 8 ml
Since 1 mL of water has the volume of 1cm^3, then the volume of the object is 8 cm^3.
The density of the object is found by the formula:
density= mass/volume= (3 g) / (8 cm^3) = 3/8 (g/cm^3)= 0.375 g/cm^3
Answer: 0.375 g/cm^3
Answer:
Step-by-step explanation:
Question 18:
arc SRQ = 360° - 98° - 115° = 147°
y = 147°/2 = 73.5°
arc SPQ = 98° + 115° = 213°
x = 213°/2 = 106.5°
Sorry, I don't know how to answer 19.
Answer:
There was 5% increase in visitors from last year to this year.
Step-by-step explanation:
Given:
Number of Visitors at theme park last year = 2000000
Number of Visitors at theme park this year = 2100000
We need to find the percent increase in visitors from last year to this year.
First we will find Number of increase in visitors from last year to this year.
Number of increase in visitors is equal to Number of Visitors at theme park this year minus Number of Visitors at theme park last year.
Framing in equation form we get;
Number of increase in visitors = 2100000 - 2000000 = 100000
Now Percent of increase in visitors is can be calculated by dividing Number of increase in visitors with Number of Visitors at theme park last year and then multiplied with 100.
Framing in equation form we get;
Percent of increase in visitors = 
Hence There was 5% increase in visitors from last year to this year.