3 years ago

(7x^2- 3y)^2 simplify

Mathematics

2 answers:

raketka [301]3 years ago

6 0

Answer:

49x^4-42x^2 y+9y^2

Step-by-step explanation:

Vedmedyk [2.9K]3 years ago

5 0

Answer:

49x^4-42x^2 y+9y^2

Step-by-step explanation:

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The length of a rectangle is one meter more than 4 times its width. Find the dimensions if the perimeter is 52 meters

vodka [1.7K]

$l=4w+1\\
2l+2w=52\\\\
2(4w+1)+2w=52\\
8w+2+2w=52\\
10w=50\\
w=5\\\\
l=4\cdot5+1\\
l=21$

5 m and 21 m

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3 years ago

at 1:00 pm you have 24 megabytes of a movie. at 1:15 pm you have 96 megabytes what is the download rate in megabytes per minute

gregori [183]

In the 15 minutes that have passed a total of 96-14 = 82 Mbs have been downloaded.

82/15 = 5.47 Mbs/min

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3 years ago

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34kurt

Answer:

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Step-by-step explanation:

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3 years ago

Seven hotdogs and four hamburgers cost $13. Four hotdogs and seven hamburgers cost $14.50. How much does one hamburger cost and

viva [34]

Answer:

hotogs=$1.50 hamburgers=$1

Step-by-step explanation:

h=hotdog b=hamburger

7h+4b=13

4h+7b=14.5

(7h+4b=13)-4b

4h+7b=14.5

h=-0.57b+1.86

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8 0

3 years ago

A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtain

slega [8]

Answer: 8359

Step-by-step explanation:

The formula for sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\frac{z_{\alpha/2}}{E})^2$

Given : The significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=z_{0.025}=\pm1.96$

Previous estimate of proportion : $p=0.32$

Margin of error : $E=0.01$

Now, the required sample size will be :-

$n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx8359$

Hence, the required sample size = 8359

5 0

3 years ago