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VikaD [51]
3 years ago
10

Three houses are mapped on a coordinate grid.

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Step-by-step explanation:

Let us consider the task to find the angle between vectors ES and EJ (the first letters are taken to name the vectors).

\overrightarrow{ES} = (4;4) - (4; -3) = \overrightarrow{(0; 7)}

ES

=(4;4)−(4;−3)=

(0;7)

​

\overrightarrow{EJ} = (-5; -4) - (4; -3) = \overrightarrow{(-9; -1)}

EJ

=(−5;−4)−(4;−3)=

(−9;−1)

​

cos \alpha=\frac{\overrightarrow{ES}*\overrightarrow{EJ}}{|\overrightarrow{EJ}|*|\overrightarrow{ES}|}cosα=

∣

EJ

∣∗∣

ES

∣

ES

∗

EJ

​

cos(a) = (0*(-9)+7*(-1)) / (7*9.055) = -0.11043;

a = 96,34°

Solution: 96 degrees.

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Read 2 more answers
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
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The general form is derived from the explicit form, which is
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t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n&#10;\\&#10;\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

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