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LuckyWell [14K]
2 years ago
10

Jeremiah's pet lizard ate 46 pounds of food during April. There are 30 days in the month April . At that rate how many days woul

d a 100 pound bag of lizard food
O About 19 days
O About 18 days
O About 15 days
O About 65 days
Mathematics
1 answer:
topjm [15]2 years ago
4 0

Answer:

about 65 days

Step-by-step explanation:

46/30 = 1.53 pounds per day

100/1.53 = about 65

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Olaf earned $416.03 commission on his sales of $9245.00. What was his rate of commission?
Crank

Answer:

$1 per $22.22 sold.

Step-by-step explanation:

To find this answer, I divided his sales by his amount earned.

9245.00/416.03=22.22

This shows the for every 22.22 dollars sold, he recieved one dollar in commission.

Hope this helped! Thanks for posting your question! If correct, please award brainliest!

8 0
3 years ago
During the first 3 days of the week, Mike read an average of 28 pages per day. During the next 4 days, Mike averaged 42 pages pe
Anestetic [448]

Answer:

36 pages per day on average

Step-by-step explanation:

Calculate the average.

3 * 28 (The first 3 days of the week where Mike reads 28 pages per day) = 84

4 * 42 (The next 4 days where Mike reads 42 pages per day ) = 168

168 + 84 = 252



To find the average using this total, divide it by the total amount of days of reading (seven days in this problem).

252 / 7 = 36

6 0
2 years ago
Helpppp pls. Rotate traingle TUV 90 degrees clockwise around the origin
lutik1710 [3]
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7 0
2 years ago
F(x) = 9x^3 + 2x^2 - 5x + 4 and g(x) = 5x^3 - 7x + 4. What is f(x) - g(x)?
sasho [114]
F(x)= 9x^3 + 2x^2 - 5x + 4 
g(x)= 5x^3 - 7x + 4

f(x) - g(x)
9x³ + 2x² - 5x + 4 - (5x³ - 7x + 4)
9x³ + 2x² - 5x + 4 - 5x³ +7x - 4
9x³ - 5x³ + 2x² -5x + 7x + 4 - 4
4x³ + 2x² + 2x 
5 0
3 years ago
Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
8 0
3 years ago
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