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Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"
Answer:
5y = x + 11
Step-by-step explanation:
Given parameters:
Equation of the line ;
y = -5x + 1
Coordinates = (2, -1)
Find the equation of a line perpendicular;
Solution:
A line perpendicular to y = -5x + 1 will have slope that is a negative inverse of the given one.
Equation of a straight line is expressed as;
y = mx + c
y and x are the coordinates
m is the slope
c is the y-intercept
So, the slope of the new line perpendicular is ;
Now let us find the y-intercept of the new line;
x = -1 and y = 2
2 = x (-1) + c
c = 2 + =
The equation of the new line is;
y = x +
or multiply through by 5;
5y = x + 11