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Mariulka [41]
3 years ago
6

A $340 item is marked down by 50%. What is the new cost of the item?

Mathematics
2 answers:
Yuri [45]3 years ago
8 0
$170 is the new cost of the item
LekaFEV [45]3 years ago
5 0

Answer: the answer is $170.00

Step-by-step explanation:

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7(6+d)=49 Solve for d.<br><br> A:d=7<br> B:d=-1<br> C:d=-7<br> D:d=1
Elan Coil [88]

Answer: d = 1

Step-by-step explanation:

First distribute the 7 to each term of (6 + d) = 42 + 7d = 49 now subtract 42 from both sides which = 7d = 7. Divide by 7 = 7d/7 = 7/7 = d = 1

3 0
3 years ago
12x+32=12x-7 how many solutions are there to the equation?
Tpy6a [65]
There are 0 solutions

5 0
3 years ago
Choose the domain for which each function is defined
klemol [59]

Answer:

Part 1) f(x)=\frac{x+4}{x} -----> x\neq 0

Part 2) f(x)=\frac{x}{x+4} ----> x\neq -4

Part 3)  f(x)=x(x+4) ----> All real numbers

Part 4) f(x)=\frac{4}{x^2+8x+16} ----> x\neq -4

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

f(x)=\frac{x+4}{x}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=0 the function is not defined

therefore

The domain is

x\neq 0

Part 2) we have

f(x)=\frac{x}{x+4}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

Part 3) we have

f(x)=x(x+4)

Applying the distributive property

f*(x)=x^2+4x

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

f(x)=\frac{4}{x^2+8x+16}

we know that

In a quotient the denominator cannot be equal to zero

so

Equate the denominator to zero

x^2+8x+16=0

Remember that

x^2+8x+16=(x+4)^2

(x+4)^2=0

The solution is x=-4

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

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3 years ago
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Answer:

you can go on something called tiger algerbra

Step-by-step explanation:

7 0
3 years ago
Mrs. Jameson asked all of her 110 students to list their birthdate and time on a sheet of paper and place it into a jar. One nam
tangare [24]
20/110 because there's 20 kids in her third period but 110 overall hope I helped in time
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