To answer this problem, we can use the power rule such that the result of the operations of the powers on the left side is equal to power on the right side. In this case, the right side's power is 200. On the left side, the tentative sum is 60 - 18 or equal to 42. Thus, the remaining exponent to be added on the left side is 158. Answer is x^158
Answer:
1
2
− 1
9
8
Step-by-step explanation:
Answer:
0.015 radians per second.
Step-by-step explanation:
They tell us that at the moment the speed would be 6 ft / s, that is, dx / dt = 6 and those who ask us is dθ / dt.
Which we can calculate in the following way:
θ = arc sin 100/200 = pi / 6
Then we have the following equation of the attached image:
x / 100 = cot θ
we derive and we are left:
(1/100) * dx / dt = - (csc ^ 2) * θ * dθ / dt
dθ / dt = 0.01 * dx / dt / (- csc ^ 2 θ)
dθ / dt = 0.01 * 6 / (- csc ^ 2 pi / 6)
dθ / dt = 0.06 / (-2) ^ 2
dθ / dt = -0.015
So there is a decreasing at 0.015 radians per second.
Let 'c' represent the number of pictures Chelsea took.
Let 's' represent the number of pictures Sonya took.
For last year's Thanksgiving, c + s = 236
For this year's Thanksgiving, let 'x' represent the number of photos taken in total. x = c + s, where c and s are two integers that are the same (c = s).
And we know that for both years, c + s + x = 500.
As we know that c + s is already 236 from last year, we can remove c + s from the equation in bold and replace it with 236 instead.
236 + x = 500.
Now we have to isolate the x term.
x = 500 - 236
x = 264.
We know that x = c + s, where c and s are the same, so we can just use one of the variables and double it (so you either get 2c or 2s - it doesn't matter which one you pick because they're both the same).
2c = 264
c = 132
c = s
s = 132.
Both took 132 pictures this year.
The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same. For example, when point P with coordinates (5,4) is reflecting across the X axis and mapped onto point P', the coordinates of P' are (5,-4).
