Answer:
C 3.10
Step-by-step explanation:
15.50 divide by 5 is 3.10
Brainliest?
Answer:
The coordinates of the point P is 14.
Step-by-step explanation:
Let point A is at 8 and B is at 16.
P is the point where the line segment in the ratio 3 : 1.
This is also where P is
rds the distance from A to B
The total distance is |16 - 8| = 8
The distance between point AB is 8 units.
of 8 is 6.
So, the point P is 6 units from A
.
8 + 6 = 14
P is at 14
Hence, the coordinates of the point P is 14.
This also works if you go 1/3 from B.
-8 is 4 from -4 which is 1/3 of 12.
Multiply x<span> and </span>3
<span>Multiply x and 1</span>
<span>The x just gets copied along.</span>
<span>The answer is x</span>
x
<span>3*x evaluates to 3x</span>
Because of the minus sign
<span>3x becomes - 3x</span>
<span>The answer is -3x</span>
<span>Multiply y and 2</span>
<span>Multiply y and 1</span>
<span>The y just gets copied along.</span>
<span>The answer is y</span>
y
<span>2*y evaluates to 2y</span>
<span>-3*x-2*y evaluates to -3x-2y</span>
<span>The answer is -3x-2y-2</span>
<span>-3*x-2*y-2 evaluates to <span>-3x-2y-2</span></span>
<span><span>so the first one is right</span></span>
<span><span>
</span></span>
Si, los dos son iguales
Cuando haces 5x=15, la división dice que x = 3. Para 2x=6 puedes usar el resultado de x=3 de la problema de antes, y cuando te usas esto va a ver que 2 de x cuando x=3 es igual a 6, y por eso 5x=15 y 2x=6 son equivalentes.
Answer:
27,0 the distance away from the school
Step-by-step explanation:
Apply the formula for equation of a straight line;
y=mx+c where c is the y intercept , and m is the gradient
From the graph, the slope is negative where speed decreases with increase in time
Find the gradient by applying the formula;

Taking y₁=24, y₂=20, x₁=9, x₂=12
Then;

write the equation of the function as ;
y=mx+c, c=36( the y-intercept when x=0) hence the equation is;

To get x-intercept, substitute value of y with 0

This means that the x-intercept is 27 ,and this means you will require 27 minutes to cover the whole distance to the school.