Sin 30 = 1/2
tan 45 = 1
Cosec 60 = 2 / √3 = 2√3 / 3
cot 45 = 1
Cos 60 = 1/2
sec 30 = 2 / √3 = 2√3 / 3
_______________________________
[ 1/2 + 1 - 2√3/3 ] ÷ [ 1 + 1/2 - 2√3/3 ] = <em>1</em>
The face and denominator of the fraction are exactly the same thus the answer is 1 .
Adding the two equations
3x + 6y + 3x - 6y = 36+0
6x = 36
x = 6
.
subtracting second equation from first
(3x + 6y ) - (3x-6y) =36 -0
12y = 36
y = 3
.
therefore
x = 6 and y = 3
(6,3)
Answer:
The process of finding the derivative of dependent variable in an implicit function by differentiating each term separately by expressing the derivative of the dependent variable as a symbol and by solving the resulting expression for the symbol.
(5y - 1) + (-2y + 4) = 5y - 1 - 2y + 4
= 5y - 2y - 1 + 4
= 3y + 3 [OPTION B]
