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Slav-nsk [51]
2 years ago
11

What is the value of the function y 2x – 3 when x = -5? A -5 B -1 C 2 D 3

Mathematics
2 answers:
aleksklad [387]2 years ago
5 0

Answer:

The answer is -1 (B)

Nutka1998 [239]2 years ago
5 0

Answer:

The answer is -1 (B)

Step-by-step explanation:

Have a good day :)

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Please help! I will give brainliest!
g100num [7]

Answer:

A

Step-by-step explanation:

trust me brother

subtracting a negative number is the same as adding the number

6 0
2 years ago
Read 2 more answers
8. Temperatures in degrees Celsius (C) may be changed to degrees Fahrenheit (F) by using the formula F = 1.8C + 32º. Find the te
pentagon [3]

Answer:

-40 °F = -40 °C

Step-by-step explanation:

(1) F = 1.8 C + 32

If the Fahrenheit and Celsius temperatures are the same, then

(2)        F = C     Substitute (2) into (1)

           C = 1.8C + 32     Subtract 1.8 C from each side

C – 1.8 C = 32                   Combine like terms

   -0.8C = 32                   Divide each side by -0.8

         C = -32/0.8

(3)      C = -40                  Substitute (3) into (1)

        F = 1.8(-40) + 32

        F = -72 + 32

       F = -40

So, -40 °F = -40 °C

The thermometer below shows that -40 °F = -40 °C.

8 0
3 years ago
Dude i have 15 mins to finish this so pls help me
kirill [66]
A) 11 (32 divided by 2 = 16 | 16 minus 5 is 11)

b) 5 + x = y | 32 minus y = number of stuffed animals

c)
Veronica has 11 stuffed animals
Mariposa has 21 stuffed animals


hope this helped gl on your test!! :”)
8 0
2 years ago
Question 3<br> Find the constant of variation (k).<br><br> -y + 9x = 0
egoroff_w [7]

Answer:

9

Step-by-step explanation:

-y + 9x = 0

y = 9x

y = kx

k = 9

3 0
3 years ago
4x-3y=2<br> 3x=5y=16<br> solve using substitution method
vodomira [7]

\left\{\begin{array}{ccc}4x-3y=2&|\text{add 3y to both sides}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}4x=3y+2&|\text{divide both sides by 4}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}x=0.75y+0.5&(*)\\3x+5y=16\end{array}\right\\\\\text{substitute}\ (*)\ \text{to the second equation}\\\\3(0.75y+0.5)+5y=16\qquad\text{use distributive property}\\\\(3)(0.75x)+(3)(0.5)+5y=16\\\\2.25y+1.5+5y=16\qquad\text{subtract 1.5 from both sides}\\\\7.25y=14.5\qquad\text{divide both sides by 7.25}

\boxed{y=2}\\\\\text{substitute the value of y to}\ (*):\\\\x=0.75(2)+0.5\\\\x=1.5+0.5\\\\\boxed{x=2}\\\\Answer:\ x=2\ and\ y=2\to(2,\ 2)

7 0
2 years ago
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