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3 years ago

14

at a nephews party you decide to write down everyone's birthday here are your result what percentage of children have their birt

hdays in december in february what percentage have their birthdays in the same month as another child at the party

1 answer:

Dafna1 [17]3 years ago

3 0

??? I don't know because you didn't state the question clearly.

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What is the value of the y-coordinate of point A?

Neko [114]

Answer:

0.26

Step-by-step explanation:

A (x , y), radius of circle = 1

y/radius = y/1 = sin 15°

y = 0.26

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3 years ago

Read 2 more answers

Algebra help?<br><br> 343 = (x/6) ^2/3

Vladimir79 [104]

I can only assume that you meant, "Solve for x:"

Apply the exponent 3/2 to both sides of this equation. The result will be

3/2

343 = x/6.

Multiplying both sides by 6 isolates x:

3/2

6*343 = x Since 7^3 = 343, the expression for x

can be rewritten as

3/2

6*(7^3) = x which can be further simplified, as follows:

x = 6^(3/2)*7^(9/2), or:

x = 6^(3/2)*7^(8/2)*√7, or

x = 6^(3/2)*7^4*√7

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3 years ago

Please help me AND ALSO PLEASE EXPLAIN HOW YOU WORKED IT OUT thank you.

lesya692 [45]

128, -512, 2048
Multiply by -4 to get each new term

4 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

or

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

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3 years ago

Find the slope of the line that passes through the origin and the point (-2,5).

Mekhanik [1.2K]

<u>Slope -2/5.</u>

Answer:

Solution given:

(x1,y1)=(0,0)

(x2,y2)=(-2,5)

now

slope =(x2-x1)/(y2-y1)=(-2-0)/(5-0)=-2/5

7 0

2 years ago