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3 years ago

14

at a nephews party you decide to write down everyone's birthday here are your result what percentage of children have their birt

hdays in december in february what percentage have their birthdays in the same month as another child at the party

1 answer:

Dafna1 [17]3 years ago

3 0

??? I don't know because you didn't state the question clearly.

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Renee, her two brothers, and her two sisters combine their money together to buy their parents a gift for the holiday season. Th

aleksklad [387]

The answer is C. because every 1 out of 5 children gave up 1/2 of their money for the gift

3 0

3 years ago

The probability that even A occurs is 5/7 and the probability that even B occurs is 2/3 are independent event's what is the prob

Crank

Answer:

The probability that A and B both occur events

$P(An B) = \frac{10}{21}=0.4761$

Step-by-step explanation:

<u>Explanation</u>:-

Given data the probability that event A occurs is 5/7

$P(A) = \frac{5}{7}$

The probability that even B occurs is 2/3

$P(B) = \frac{2}{3}$

<u>Independent events:-</u>

If the occurrence of the event 'B' is not effected by the occurrence or non-occurrence of the event 'A' , then the event 'B' is said to be independent of A.

A and B are independents events P(A∩B) = P(A) P(B)

The probability that A and B both occur events

P(A∩B) = P(A) P(B)

$P(A nB) = \frac{5}{7} X \frac{2}{3}$

$P(An B) = \frac{10}{21}$

$P(An B) = \frac{10}{21}=0.4761$

<u>Conclusion:-</u>

The probability that A and B both occur events

$P(An B) = \frac{10}{21}=0.4761$

3 0

3 years ago

Item 7 Complete the statement. Round to the nearest hundredth if necessary. 64 lb ≈ kg

Marina CMI [18]

Answer:

64 lb = 29.029912 kg

Rounded to the nearest hundredth is 29.03 kg

hope this helps!

7 0

3 years ago

Are 1/2 and 12/24 and 13/26 equivalent?

vesna_86 [32]

Yes because 12 is a half of 24 and 13 is a half of 26 which all equal to 1/2 . So the answer is YES

4 0

3 years ago

How many different ways can the letters of “football” be arranged

makvit [3.9K]

<h3>Answer: 10,080</h3>

Explanation:

There are 8 letters so there are 8! = 8*7*6*5*4*3*2*1 = 40,320 permutations of those letters. However, the letters "O" and "L" show up twice each, so we must divide by 2! = 2*1 = 2 for each instance this happens.

So,

(8!)/(2!*2!) = (40,320)/(2*2) = (40,320)/4 = 10,080

is the number of ways to arrange the letters of "football".

The reason we divide by 2 for each instance of a duplicate letter is because we can't tell the difference between the two "O"s or the two "L"s. If there was a way to distinguish between them, then we wouldnt have to divide by 2.

3 0

3 years ago