Answer:
Step-by-step explanation:
1. 5x-2=3x+4
+2 +2
2. 5x=3x+6
-3x -3x
3. 2x=6
/2 /2
x=3
Move constant to the right-hand side and change its sign
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x
Answer:
the volume will be 56 m³
because it is made of 56 cubes of 1m ³ volume
I hope it helps
Answer:
D
x=-4+2√2 or x=-4-2√2
Step-by-step explanation:
3(x+4)²-24
3(x+4)²=24
(x+4)²=24/3
(x+4)²=8
x+4=√8
x+4=±2√2
x=-4+2√2 or x=-4-2√2
Answer:
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Step-by-step explanation:
The equation for the volume of a pyramid of base area B and height h is
V = (1/3)·B·h. Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown. First we find the height of this pyramid, and then the slant height.
V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.
Now to find the slant height of this pyramid: That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).
Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
