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lesya [120]
3 years ago
6

Is (-a + b)² = a² - 2ab + b² right or wrong, and why?

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:

\huge\boxed{\sf Right.}

Step-by-step explanation:

(-a+b)^2

Let's apply the formula (x+y)² = x² + 2xy + y²

Here, x = -a and y = b

So,

= (-a)² + 2(-a)(b) + (b)²

= a² - 2ab + b²

Hence, it has been proved that (-a + b)² = a² - 2ab + b².

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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Use the functions to answer the question.
Lelechka [254]

Answer:

3 and 9

if f(x)=x^2+13 and g(x)=12x-14

Step-by-step explanation:

So when we are looking for the intersection of two functions, we are trying to figure out when they are the same.  When you think same, you should think equal (=).

So we want to find when f(x)=g(x) for x.

f(x)=g(x)

x^2+13=12x-14

Let's get everything to one side.

Subtracting 12x and adding 14 to both sides.

x^2+13+14-12x=0

I'm going to reorder the left hand side and also simplify the 13+14 part:

x^2-12x+27=0

Now since the coefficent of x^2 is just 1 our job is to find two numbers that multiply to be 27 and add up to be -12.

Those numbers are -3 and -9 since -3(-9)=27 and -3+(-9)=-12.

So the factored form of our equation is

(x-3)(x-9)=0

Since the product is 0, then at least one of the factors must be 0.

So we want to solve both x-3=0 and x-9=0.

x-3=0 can be solved by adding 3 on both sides. This gives us x=3.

x-9=9 can be solved by adding 9 on both sides. This gives us x=9.

The intersection of f and g happens at x=3 or x=9.

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