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Gelneren [198K]
3 years ago
9

9.77x10^5 1SF In standard form

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer: 977000

Step-by-step explanation:

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Given:

The figure of a right triangle ABC.

To find:

The trigonometric ratios \sin B, \tan A, \cos B.

Solution:

Using Pythagoras theorem,

Hypotenuse^2=Perpendicular^2+Base^2

AB^2=AC^2+BC^2

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Taking square root on both sides.

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So, measure of BC is 8 units.

Now,

\sin \theta=\dfrac{Opposite}{Hypotenuse}

\sin B=\dfrac{AC}{AB}

\sin B=\dfrac{6}{10}

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Similarly,

\tan \theta=\dfrac{Opposite}{Adjacent}

\tan A=\dfrac{AC}{BC}

\tan A=\dfrac{6}{8}

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And,

\cos \theta=\dfrac{Adjacent}{Hypotenuse}

\cos B=\dfrac{BC}{AB}

\cos B=\dfrac{8}{10}

\cos B=\dfrac{4}{5}

Therefore, the required trigonometric ration are \sin B=\dfrac{3}{5}, \tan A=\dfrac{3}{4}, \cos B=\dfrac{4}{5}.

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3 years ago
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Answer:

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Step-by-step explanation:

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vekshin1

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Anwer

\sqrt{7}

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\pi

\sqrt{17}

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Step-by-step explanation:

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