Question

Two dice are tossed and the magnitude of the difference in the number of dots facing up in the two dice is noted. (a) What is the sample space of the event of tossing of the two dice

Answer 1

Answer:

Sample space S = {0,1,2,3,4,5}

Step-by-step explanation:

We all know that when a dice is tossed, the minimum value that can be obtained is 1 and the maximum value that can be obtained is 6.

Now, when two dice are tossed, the possible cases are:

$= \left\{\begin{array}{cccccc}(1,1)&(1,2)&(1,3) &(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3) &(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3) &(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3) &(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3) &(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3) &(6,4)&(6,5)&(6,6)\end{array}\right\}$

However, the magnitude of the difference in no. of dots showing up in the two dice is:

$= = \left\{\begin{array}{cccccc}(1,1)=0&(1,2)=1&(1,3)=2 &(1,4)=3&(1,5)=4&(1,6)=5\\(2,1)=1&(2,2)=0&(2,3)=1 &(2,4)=2&(2,5)=3&(2,6)=4\\(3,1)=2&(3,2)=1&(3,3)=0 &(3,4)=1&(3,5)=2&(3,6)=3\\(4,1)=3&(4,2)=2&(4,3)=1 &(4,4)=0&(4,5)=1&(4,6)=2\\(5,1)=4&(5,2)=3&(5,3)=2 &(5,4)=1&(5,5)=0&(5,6)=1\\(6,1)=5&(6,2)=4&(6,3)=3 &(6,4)=2&(6,5)=4&(6,6)=0\end{array}\right\}$

Thus, the sample space Sample space-related when two dice are tossed & the magnitude is:

S = {0,1,2,3,4,5,}