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2 years ago

Can someone do my hw for me

Mathematics

1 answer:

IrinaVladis [17]2 years ago

6 0

Answer:

depends on what the homework is

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If y is directly proportional to x and y = 17.5 when x=21 find y when x=39

morpeh [17]

direct proportion y=kx , k is constant and k does not equal to 0.

17.5=k(21)

k=5/6

when x =39

y=5/6 ×39

y=32.5

4 0

3 years ago

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Karo-lina-s [1.5K]

3 + 8 = 12 and 8 + 3 = 12

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3 years ago

8m + 5n for m= 3 and n=-5

sasho [114]

Answer:

- 1

Step-by-step explanation:

8m + 5n

8(3) + 5(- 5)

24 + (- 25)

24 - 25

- 1

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3 years ago

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Which expression is equivalent to 60x^20y^24/30x^10y^12 ?

olganol [36]

Answer:

2x^(10)y^(12)

Hope This Helps! Have A Nice Day!!

8 0

3 years ago

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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago