Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
I'm pretty sure that it's b. That's assuming that you find the negative of b^2 and not the square of negative b.
Answer:
the width would be 4 inches and the length would be 6 inches
reflection of 
over the y axis we get 
Step-by-step explanation:
We need to find the reflection of f(x)=sqrt x over the y axis
So, reflection over y- axis
If the function f(x) is transformed over y-axis then the new function g(x) will be 
So, finding reflection of over the y axis we get:
So, reflection of over the y axis we get
Keywords: Transformations
Learn more about Transformations at:
#learnwithBrainly
Answer:
Step-by-step explanation:
a = 180 - 100
= 80 degrees
b = 180 - 80
= 100 degrees
c = 180 - 135
= 45 degrees
