If there are n people, each person could shake hands with 0 people, 1 person, 2 people,... on up to shaking hands with n − 1
people. Count how many different answers there are to asking the person the question "How many hands did you shake?" How many people are there? If the people are the pigeons, and the possible answers to the question "how many hands did you shake" are the holes, can we conclude anything yet? No? How about now noticing that at least one of the holes "I shook hands with noone" or "I shook hands with everyone" has to be empty... now what?
"Since there are more pigeons than holes there must be a hole with at least two pigeons in the same hole" Now, replace the word "pigeons" and "holes" with the appropriate terms for the context of your specific question, remember we are talking about people and number of handshakes they participated in.
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
Answer:
tan A = -15/8.
Step-by-step explanation:
sin^2a = 1 - cos^2A
= 1 - (-8/17)^2
= 225/289
So sin A= 15/17
tan A = sin A / cos A
= 15/17 / -8/17
= 15/-8
= -15/8.
9514 1404 393
Answer:
3 1/3
Step-by-step explanation:
Multiply both sides by the reciprocal of the coefficient of c.
(5/2c)(2/5) = (8 1/3)(2/5)
c = (25/3)(2/5) = 50/(3·5) = 10/3
c = 10/3 = 3 1/3
