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2 years ago

Bub buys a t - shirt for $7.45. He pays with a $20 bill . How much change will he get

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

7 0

Answer:

12.55

Step-by-step explanation:

You might be interested in

Zahin has 4/6

LenKa [72]

Answer:

2/15 or 0.13

Step-by-step explanation:

first you multiply 2/3 and 1/5 which gets you 2/15

7 0

3 years ago

Read 2 more answers

A refrigeration system at your company uses temperature sensors fixed to read Celsius (0C) values, but the system operators in y

solmaris [256]

Answer:

14 °F

Step-by-step explanation:

To answer this problem, we will use the known celsius to fahrenheit conversion formula.

[Celsius * (9/5)] + 32 = Fahrenheit

Now we just plug in the value of celsius:

[-10 * (9/5)] + 32 = Fahrenheit

[ -2 * 9 ] + 32 = Fahrenheit

[ -18 ] + 32 = Fahrenheit

14 = Fahrenheit

So you should right 14(°F) on the label.

Cheers.

5 0

2 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

A sphere is just enclosed inside a right circular cylinder. If the volume of the sphere is 140 cm3, find the volume of the gap b

alexgriva [62]

-----------------------------------------------------------
Find Radius :
-----------------------------------------------------------
$\text {Volume of a sphere =} \dfrac{4}{3} \pi r^3$

$\dfrac{4}{3} \pi r^3 = 140$

$\pi r^3 = 140 \times \dfrac{3}{4}$

$\pi r^3 = 105$

$r^3 = \dfrac{105}{ \pi}$

$r = 3.22 \ cm$

-----------------------------------------------------------
Find volume of the cylinder :
-----------------------------------------------------------
$\text {Volume of the cylinder = } \pi r^2h$

$\text {Volume of the cylinder = } \pi ((3.22)^2(3.22 \times 2)$

$\text {Volume of the cylinder = } 209.77 \ cm^3$

-----------------------------------------------------------
Find volume of the gap :
-----------------------------------------------------------
$\text {Volume of gap = } 209.77 - 140$

$\text {Volume of gap = } 69.77 \ cm^3$

-----------------------------------------------------------
$\bf \text {Answer : } 69.77 \cm^3$
-----------------------------------------------------------

6 0

3 years ago

Which figure has 2 pairs of parallel sides 2 pairs of sides of equal length and 4 right angle

elixir [45]

The figure is a parallelogram.

3 0

3 years ago