For which of the following intervals is the graph increasing

Please no spammers, I just need help on overdue homework!

Alex Ar [27]

She should choose data 1! I can’t see the graph

6 0

3 years ago

How can finding the number of solutions apply to the real world?<br> need answer fest plz

Inessa05 [86]

Answer:

it helps sharpen ur brain up for future so as not to be cheated by others

6 0

3 years ago

A polynomial function has a zero at x=3 which of the follwing expressions must be one factor of the polynomial. A. x + 3 b. 3x C

nexus9112 [7]

I think the correct answer from the choices listed above is option D. A polynomial function has a zero value at x=3 for the <span>expression where one factor is x-3. This factor when x=3 will always result to a zero value no matter what you multiply to it. Hope this answers the question.</span>

5 0

3 years ago

Read 2 more answers

Evaluate y when x=-5. y=3x-6

Sav [38]

Answer:

x= -5

y= -21

Step-by-step explanation

I hope that is the answer you are looking for!And Brainiest is needed!

4 0

3 years ago

Read 2 more answers

A survey showed that 77% of us need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. 13 adults are randomly

earnstyle [38]

Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

A survey showed that 77% of us need correction, hence p = 0.77.

13 adults are randomly selected, hence n = 13.

The probability that at least 12 of them need correction for their eyesight is given by:

$P(X \geq 12) = P(X = 12) + P(X = 13)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299$

$P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334$

Then:

$P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163$

The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

More can be learned about the binomial distribution at brainly.com/question/24863377

7 0

3 years ago