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2 years ago

150-(2+x)^3 when x equals 2

Mathematics

2 answers:

Schach [20]2 years ago

8 0

Answer:

Step-by-step explanation:

150 - (2 + x)³

=> 150 - (2 + 2)³

=> 150 - (4)³

=> 150 - 64

=> 86

Therefore, 86 is the correct answer.

stira [4]2 years ago

7 0

Hey!

Let's work through this problem together.

1st and most important step is that we use order of operations as we go left to right.

P.E.M.D.A.S: Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.

First, The parenthesis, which is (2+x), or (2+2), which is 4.

So now, the equation looks like: 150-4^3.

Next, Exponents. 4^3 is 4x4x4. 4x4=16. 16x4=64.

So now the equation looks like this: 150-64.

Lastly, we subtract. 150-64=86.

<h2>So, your answer is 86.</h2><h2 />

Hope this helps!

<h2><em>~~~PicklePoppers~~~</em></h2>

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

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Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
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And, with the second equation:

3x + y = 5
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