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Answer: I have the pictures attached
Step-by-step explanation:
In order to graph this, we have to get it into this equation: y = mx + b, where m = slope and b = y intercept.
y = 3/2x - 4 is already in this form.
2y + 4 = 2 + 3x is not, so we have to isolate y
2y + 4 - 4 = 2 + 3x - 4
2y = -2 + 3x
2y/2 = -2/2 + 3x/2
y = -1 + 3/2x
y = 3/2x - 1
Okay, now graph it knowing your y intercepts and your slopes.
Area of the figure = 806.5 in²
Solution:
Length of the rectangle = 16 in
Breadth of the rectangle = 9 in
Area of the rectangle = length × breadth
= 16 × 9
Area of the rectangle = 144 in²
Base of the triangle = 31 in
Height of the triangle = 20 in
Area of the triangle =
Area of the triangle = 310 in²
Parallel sides of the trapezium = 16 in and 31 in
Height of the trapezium = 35 – 20 = 15 in
Area of the trapezium =
Area of the trapezium = 352.5 in²
Area of the figure = Area of rectangle + Area of triangle + Area of trapezium
= 144 in² + 310 in² + 352.5 in²
Area of the figure = 806.5 in²