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2 years ago

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PLEASE PLEASE PLEASE PLEASE (5'1, 5'2, 5'3, 5'4, 5'5, 5'6, 5'7, 5'8, 5'9, 5'9, 5'10, 5'11, 5'12) PLEASE FIND THE ABSOLUTE DEVIAT

ION MAN PLEASE

1 answer:

crimeas [40]2 years ago

7 0

Answer:

Answer:

A. mean: 5.75

B. 1.8958

Thank you! Please mark me brainliest so that I get encouraged to answer more great questions like this one!

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Write the equation of a line that is parallel to {x=8}x=8x, equals, 8 and that passes through the point {(-3,-2)}(−3,−2)left par

Alexxandr [17]

Answer:

x = -3

Step-by-step explanation:

The line parallel to x=8 is another vertical line:

x = constant

To make it go through a point with an x-coordinate of -3, the constant must be -3.

Your line is ...

x = -3

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4 years ago

A basketball gymnasium is 25 meters high, 80 meters wide and 200 meters long. We want to connect two strings, one from each of t

Rudiy27

Answer:

a) the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be 216.85 m

c) the angle that is formed by the strings is 1.23 rad

Step-by-step explanation:

assuming that we stand on one of the corners on the floor , so our coordinates are (0,0,0) , then the coordinates of the center of the gymnasium are found through

x center = (25 + 0)/2 = 12.5 m

y center = (80+ 0)/2 = 40 m

z center = (200+ 0)/2 = 100 m

then the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be the modulus of the vector that points from our position to the diagonally opposite corners

|S| = √(25²+80²+200²) = 216.85 m

c) the angle can be found through the dot product of the vectors that represent the strings S₁ and S₂

S₁ =(25,80,10)

S₂ =(-25,80,100)

then

S₁*S₂ = 25*(-25) +80*80 + 100*100 = 15775

but also

S₁*S₂ = |S₁||S₂| cos θ = |S|² * cos θ

S₁*S₂ = |S|² * cos θ

cos θ= S₁*S₂/|S|²

θ= cos ⁻¹ ( S₁*S₂/|S|² ) = cos ⁻¹ [15775/(25²+80²+200²)] = 1.23 rad

7 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

7 0

3 years ago

Find the volume of a right circular cone that has a height of 11.8 ft and a base with a radius of 7.3 ft. Round your answer to t

lora16 [44]

Answer:

The answer to your question is 658.2 ft³

Step-by-step explanation:

Data

Volume = x

height = 11.8 ft

radius = 7.3 ft

Formula

Volume of a cone = 1/3πr²h

Process

1.- Calculate the volume

Volume = 1/3(3.14)(7.3)²(11.8)

Volume = 1/3(3.14)(7.3)²(11.8)

Volume = 1/3(3.14)(53.29)(11.8)

Volume = 1/3(1974.5)

Rounded to the nearest tenth

Volume = 658.2 ft³

3 0

3 years ago

What is 0.316 in expanded form

Inessa [10]

<span>0.316 in expanded form is= 0.3 + 0.01 + 0.006. </span>

5 0

3 years ago