From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.
Answer: 3rd one
Rearrange the original equation so it fits the model of : ax^2+bx+c=0
Then use the quadratic formula to find all possible answers.
M=-1/2 because you do y1-y2 over x1-x2 and end up with 2/-4 but simplified is -1/2