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miss Akunina [59]
2 years ago
5

1. The total amount of what you eam during the pay period before taxes and deductions are taken out is known as what?

Mathematics
1 answer:
OLga [1]2 years ago
8 0

Answer:

net pay if im not mistaking

Step-by-step explanation:

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Please please help i’ll give brainliest tysm :)
Neko [114]

Answer:

C) Between 9 and 13

Step-by-step explanation:

If 40% is 5 gallons, then 20% is 2.5 gallons

If you multiply both by 5, you get 12.5, which is between 9 and 13

Sorry for my weird way of math

3 0
3 years ago
Read 2 more answers
If Erica has 7$ And her sister holly has some money too how much do they have in total
Dmitry [639]

Answer:

you cant figure that out.

Step-by-step explanation:

6 0
3 years ago
Using =2L+2W, Find L when P is 50 and W is 10
mestny [16]

Answer:

L = 15

Step-by-step explanation:

P = 2L + 2W

you know that P = 50, W=10

So you have to replace those values on the equation

50 = 2L + 2*(10)  --> Replace P and W

50 = 2L + 20  --> Multiply and now you are going to separate the unknown and the constants.

Remember that if you send a constant to the other side of the equal the sign will change to its opposite

50 - 20 = 2L  --> Solve the constants

30 = 2L    --> Now for the L, you have to leave it alone, so the 2 that is multiplying you have to send it to the other side of the equal but with the opposite operation,  the opposite operation of multiplying is dividing, so you have:

30/2 = L

L= 15

5 0
4 years ago
Please help i only have like 10 more minutes!:)
skelet666 [1.2K]

Answer:

14 months

Step-by-step explanation:

150 - 24 = 126 then divided by 9 which = 14 so it will take 14 months to get 150

4 0
3 years ago
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
3 years ago
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