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UkoKoshka [18]
4 years ago
11

Divide the following complex numbers (2 + i ) ÷ ( 1 - 4i ) ​

Mathematics
2 answers:
Dvinal [7]4 years ago
5 0

-2/17 + 9i/17 fractions

tiny-mole [99]4 years ago
3 0

Answer:

- \frac{2}{17} + \frac{9}{17} i

Step-by-step explanation:

Multiply the numerator/denominator by the complex conjugate of the denominator.

The conjugate of 1 - 4i is 1 + 4i

\frac{(2+i)(1+4i)}{(1-4i)(1+4i)} ← expand factors

= \frac{2+9i+4i^2}{1-16i^2} → i² = - 1

= \frac{2+9i-4}{1+16}

= \frac{-2+9i}{17}

= - \frac{2}{17} + \frac{9}{17} i

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Agree. 70% of 25 is 18

Step-by-step explanation:

6 0
3 years ago
Here is an inequality: -2x>10
jek_recluse [69]

Answer:

The right solution is "x>-5".

Step-by-step explanation:

The given inequality is:

⇒ -2x>10

By solving the above expression, we get

⇒ x >-\frac{10}{2}

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Thus the above is the correct answer.

7 0
3 years ago
2x+3x+4
ivolga24 [154]
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Given vectors U = (7,4) and v = (1,-1), find the sum u + v and write the
levacccp [35]

Answer:

u + v = < 8, 3 >

Step-by-step explanation:

u + v

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= < 7 + 1, 4 - 1 >

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7 0
3 years ago
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Sum of (x+5) and (2x+3)
olga55 [171]

Answer:

3x+8

Step-by-step explanation:

First, we can write the sum into a <em>mathematical expression</em>:

<em>The sum of (x+5) and (2x+3)</em>

<em />

<u>(x+5)+(2x+3)</u>

<u />

<em>However, we do not need the parenthesis. It is unnecesarry here as we are just adding the two parts:</em>

<em />

<u>x+5+2x+3</u>

<u />

Using <em>commutative property</em>, we can rearrange the symbols so that the x's are with each other and the numbers are with each other:

<u>x+2x+5+3</u>

<u />

Now we can <em>simplify</em> the expression:

<u>3x+8</u>

<u />

Hope this helped :)

5 0
3 years ago
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