Ask question

Ask question

All categories

2 years ago

6

Can someone help me?

1 answer:

I am Lyosha [343]2 years ago

4 0

Answer:

j=5√80vπ⁴/2π

Step-by-step explanation:

Take the root of both sides and solve.

j=5√80vπ⁴/2π

-hope it helps

You might be interested in

Round 2,165.413 to the nearest hundredth.

stira [4]

2,200.413 is 2,165.413 to its nearest hundredth.

4 0

3 years ago

The diameter of a meteorite in millimeters is calculated by four different methods. Order the results from least to greatest. Ex

grandymaker [24]

Answer:

√18, 13/3, 4.6, 4π

Step-by-step explanation:

joe = √18 = 4.24 mm

Lisa = 13/3 = 4.33 mm

Pablo = 4.6 = 4.60 mm

Julien = 4π = 12.56 mm

8 0

3 years ago

1+1+1+1+2-200 pls quick

Ksenya-84 [330]

You add up 1+1+1+1+2 and you get 6. You then subtract 6 by 200 and your answer is -194

5 0

4 years ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

3 years ago

Noam chose 3 songs from a pile of 20 songs to play at a piano recital. What is the probability that she chose The Entertainer, S

Alenkasestr [34]

$|\Omega|={_{20}C_3}=\dfrac{20!}{3!17!}=\dfrac{18\cdot19\cdot20}{2\cdot3}=1140\\|A|=1\\\\P(A)=\dfrac{1}{1140}\approx0.09\%$

6 0

3 years ago

Read 2 more answers