Answer:
It will roll up to its initial height from which it rolled from on the first hill
Explanation:
The given information are;
The height from which the ball is rolled = 3 feet[
The equation of the potential energy of the ball as it rolled down the frictionless inclined plane is given by the following equation;
m × g × h₁ = 1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r]
Where;
m = The mass of the ball
h = The from which the ball is rolled down
v = The velocity of the ball
r = The radius of the ball
Therefore, all the potential energy, m × g × h, is converted into kinetic energy when the ball reached the ground
Similarly, as the ball rolls up on the other side, by the principle of energy conservation, all the kinetic energy is transformed into potential energy as follows
1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₂, therefore, we have;
1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₁ = m × g × h₂
Therefore since m × g × h₁ = m × g × h₂, then h₁ = h₂, the ball rises to the same height it started rolling from on the first hill.
