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3 years ago

M = 15 kg, a = 2 m/s2, F =

Physics

1 answer:

Lisa [10]3 years ago

7 0

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 15 × 2

We have the final answer as

Hope this helps you

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A 0.70-kg disk with a rotational inertia given by MR 2/2 is free to rotate on a fixed horizontal axis suspended from the ceiling

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Answer:

The force will be "9.8 N".

Explanation:

The given values are:

mass,

m = 0.7 kg

M = 2

g = 9.8

Now,

⇒ $\tau = T \alpha$

then,

⇒ $\frac{1}{2}mR^2(\frac{1}{R}\frac{dv}{dt}) =M(g-a_t)R$

⇒ $\frac{1}{2}m \ a_t=m(g-a_t)$

⇒ $a_t=\frac{2g}{(\frac{m}{M} +2)}$

On substituting the values, we get

⇒ $=\frac{2\times 9.8}{\frac{0.7}{2} +2}$

⇒ $=8.34 \ m/s$

hence,

⇒ $T=mg+M(g-a_t)$

On substituting the values, we get

⇒ $=0.7\times 9.8+2(9.8-8.34)$

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3 years ago

How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 23.0 cm in diameter to p

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Answer:

10573375000

$216.57162\ N/C$

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

r = Distance = $\dfrac{d}{2}=\dfrac{23}{2}=11.5\ cm$

E = Electric field = 1150 N/C

Electric field is given by

$E=\dfrac{kq}{r^2}\\\Rightarrow q=\dfrac{Er^2}{k}\\\Rightarrow q=\dfrac{1150\times 0.115^2}{8.99\times 10^9}\\\Rightarrow q=1.69174\times 10^{-9}\ C$

Number of electrons is given by

$n=\dfrac{1.69174\times 10^{-9}}{1.6\times 10^{-19}}\\\Rightarrow n=10573375000$

Number of excess electrons is 10573375000

r = 0.115+0.15 = 0.265 m

$E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times 1.69174\times 10^{-9}}{0.265^2}\\\Rightarrow E=216.57162\ N/C$

The electric field is $216.57162\ N/C$

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