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muminat
2 years ago
8

. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point)

Mathematics
2 answers:
Elodia [21]2 years ago
7 0

\\ \sf\longmapsto f(x)=\sqrt{x+7}

\\ \sf\longmapsto g(x)=8x-11

  • g(x) will be put on the place of x

\\ \sf\longmapsto f(g(x))=\sqrt{8x-11+7}

\\ \sf\longmapsto f(g(x))=\sqrt{8x-4}

\\ \sf\longmapsto f(g(x))=\sqrt{4(2x-1)}

\\ \sf\longmapsto f(g(x))=2\sqrt{2x-1}

charle [14.2K]2 years ago
5 0

Answer:

2 sqrt(2x-1)

Step-by-step explanation:

f(x) = sqrt( x+9)

g(x) = 8x-13

f(g(x))

place the function g(x) in for x in f(x)

f(g(x)) = sqrt(8x-13+9)

Combine like terms

f(g(x)) = sqrt(8x-4)

Factor out 4

f(g(x)) = sqrt(4*(2x-1)

           2 sqrt(2x-1)

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Y=4 -2x<br> у = -5 + 4х<br> ||
kolezko [41]

Answer:

y=1

Step-by-step explanation:

y= 4 - 2x

y= -5 + 4x

4 - 2x = -5 + 4x

4 + 5 = 4x +2x

9 = 6x

9/6 = x

3/2 = x

y= 4 -2(3/2)

y = 4 - 3

y = 1

5 0
2 years ago
Identify the equation in slope-intercept form for the line containing the point (2,1) and parallel to y=5/3x−1/3.
Murljashka [212]

Answer:

A

Step-by-step explanation:

7 0
2 years ago
Two vertical posts stand side by side. One post is 8 feet tall and the other is 17 feet tall. If a 24 foot wire is stretched bet
lianna [129]

Answer:

The distance between the posts is 3\sqrt{55} feet.

Step-by-step explanation:

In the attached figure, let DB and AC be the posts and let AD be the wire attached to the top of the posts.

BC is the distance between the posts and we need to find BC.

Note that BC = DE

Also, EC = DB = 8m and AE = AC - EC = 17 - 8 = 9 m.

Now, in the right triangle ADE,

AD^{2} =AE^{2} +DE^{2}

24^{2} =9^{2} +DE^{2}

DE^{2} =24^{2} -9^{2}

= (24+9) (24-9)

= 33(15)

= (3 × 11) × (3 × 5)

DE=3\sqrt{55}

Since DE = BC,

BC=3\sqrt{55}

Hence, the distance between the posts is 3\sqrt{55} feet.



7 0
2 years ago
Been stuck on this for a while now, some help would be nice.
vampirchik [111]

Answer:

20 total claustrophobic candy bars were in the machine

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
bridget went fishing with her dad. Bridget caught the first fish of the day and it weighed f ounces. that day she caught four mo
marishachu [46]

Assuming all the fishes caught by Bridget and her dad have the same total weight, then the first fish Bridget caught would weigh <u>5 ounces</u> while the first fish caught by her dad weighed <u>17 ounces</u>.

<h3>What is weight?</h3>

Weight can be defined as the force acting on an object or a physical body due to the effect of gravity. Also, the weight of a physical object (body) is typically measured in Newton or ounces.

<h3>How to calculate the weight of the first fish?</h3>

First of all, we would determine the weight of all of the fishes caught by both Bridget and her father (dad) while translating the word problem into an algebraic equation as follows:

For Bridget, we have:

Bridget's fish = f + 2f + 3f + 2 + ½f + ⅗f

Bridget's fish = 7 f/10 + 2      ......equation 1.

For her dad, we have:

Dad's fish = 3f + 2 + ⅘f + 2f + 4 + ½f

Dad's fish = 6 3f/10 + 6            ......equation 2.

Equating eqn. 1 and eqn. 2, we have:

7 f/10 + 2 = 6 3f/10 + 6

7 f/10 - 6 3f/10 = 6 - 2

8f/10 = 4

8f = 40

f = 40/8

Bridget, f = 5 fishes.

Since her dad's fish weighed 2 more than 3 times, we have:

Dad = 3f + 2

Dad = 3(5) + 2

Dad = 15 +2

Dad = 17 ounces.

In conclusion, the first fish Bridget caught would weigh <u>5 ounces</u> while the first fish caught by her dad weighed <u>17 ounces</u> assuming all the fishes caught by Bridget and her dad have the same total weight.

Read more on word problems here: brainly.com/question/13170908

#SPJ1

Complete Question:

Bridget went fishing with her dad. Bridget caught the first fish of the day, and it weighed f ounces. That day, she caught four more fish. One was 2 times the weight of the first fish, another was 2 more than 3 times the weight of the first fish, the next was 1/2 the weight of the first fish, and the last was 3/5 the weight of the first fish. Bridget’s dad caught four fish. The first fish he caught weighed 2 more than 3 times the weight of the first fish caught that day. One fish weighed 4/5 the weight of the first fish caught that day, one weighed 4 more than 2 times the weight of the first fish caught that day, and the last weighed 1/2 the weight of the first fish caught that day.

If all the fish Bridget caught have the same total weight as all the fish her dad caught, then the first fish Bridget caught weighed___ ounces and the first fish her dad caught___ weighed ounces.

4 0
2 years ago
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