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muminat
2 years ago
8

. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point)

Mathematics
2 answers:
Elodia [21]2 years ago
7 0

\\ \sf\longmapsto f(x)=\sqrt{x+7}

\\ \sf\longmapsto g(x)=8x-11

  • g(x) will be put on the place of x

\\ \sf\longmapsto f(g(x))=\sqrt{8x-11+7}

\\ \sf\longmapsto f(g(x))=\sqrt{8x-4}

\\ \sf\longmapsto f(g(x))=\sqrt{4(2x-1)}

\\ \sf\longmapsto f(g(x))=2\sqrt{2x-1}

charle [14.2K]2 years ago
5 0

Answer:

2 sqrt(2x-1)

Step-by-step explanation:

f(x) = sqrt( x+9)

g(x) = 8x-13

f(g(x))

place the function g(x) in for x in f(x)

f(g(x)) = sqrt(8x-13+9)

Combine like terms

f(g(x)) = sqrt(8x-4)

Factor out 4

f(g(x)) = sqrt(4*(2x-1)

           2 sqrt(2x-1)

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two trains leaves stations 320miles apart at the same time and travel toward eachother. One train travels at 110 miles per hour
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x/110 = (320-x)/90

<span> Cross multiply</span>

90x = 35200-110x

200x=35200

X = 35200/200 = 176 (distance traveled by train going 110 mph

176/110 = 1.6 hours = 1 hour and 36 minutes

 

Check: 110*1.6 = 176, 90*1.6 = 144

176+144 = 320

it will take 1.6 hours ( 1 hour 36 minutes) for the trains to meet
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If a test consists of ten multiple choice questions with each permitting a possible answers. How many ways are there in which a
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Answer:

10048576 ways

Step-by-step explanation:

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This will also apply if we have more than 1 question with the same number of options.

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Read 2 more answers
The polar curve $r = 1 + \cos \theta$ is rotated once around the point with polar coordinates $(2,0).$ What is the area of the r
mash [69]

Answer:

Area = -2.3147

Step-by-step explanation:

Given

$r = 1 + \cos \theta$

Required

Determine the area with coordinates (2,0)

The area is represented as:

Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta

Where

$r = 1 + \cos \theta$

and

(a,b) = (2,0)

Substitute values for r, a and b in

Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta

Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)^2} \, d\theta

Expand

Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)(1 + cos\theta)} \, d\theta

Area = \frac{1}{2}\int\limits^0_2 {(1 + 2cos\theta+cos^2\theta} )\, d\theta

By integratin the above, we get:

Area = \frac{1}{2}*\frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{2}[0,2]

Area = \frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{4}[0,2]

Substitute 0 and 2 for \theta one after the other

Area = \frac{(cos(0) + 4)sin(0) + 3*0}{4} - \frac{(cos(2) + 4)sin(2) + 3*2}{4}

Area = \frac{(cos(0) + 4)sin(0)}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}

Area = \frac{(1 + 4)*0}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}

Area =  - \frac{(cos(2) + 4)sin(2) + 6}{4}

Area =  \frac{-sin(2)(cos(2) + 4) - 6}{4}

Get sin(2) and cos(2) in radians

Area = \frac{-0.9093 * (-0.4161 + 4) - 6}{4}

Area = \frac{-9.2588}{4}

Area = -2.3147

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2 years ago
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