Answer:
Step-by-step explanation:
The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.
Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:
Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
g = 118°, h = 62°, k = 140°, m = 40°
Step-by-step explanation:
g = 118°
h = 180 - 118 = 62°
k = 140°
m = 180 - 140 = 40°
The trapezoid was translated Right 6 ,down 5
