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mote1985 [20]
2 years ago
13

109⁰+118⁰+44⁰=× can you please help​

Mathematics
1 answer:
Paha777 [63]2 years ago
6 0

Answer:

x = 271 degrees

Step-by-step explanation:

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Line d is parallel to line c in the figure below. Parallel lines d and c are intersected by lines q and p to form 2 triangles. A
Verdich [7]

Answer:

A  B  C

Step-by-step explanation:

6 0
3 years ago
WILL GIVE BRAINLY Find the perimeter of the figure below, in meters.
yan [13]

Answer:

147.6\:\mathrm

Step-by-step explanation:

The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.

Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:

9.8+9.8+11.7+9.8+21.5+21+11.7+9.8+31.3+11.2=\boxed{147.6\:\mathrm{m}}

Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.

3 0
3 years ago
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
PLz help me this is 7th grade math
UkoKoshka [18]

Answer:

g = 118°, h = 62°, k = 140°, m = 40°

Step-by-step explanation:

g = 118°

h = 180 - 118 = 62°

k = 140°

m = 180 - 140 = 40°

5 0
3 years ago
Help me on this question please. Thx
lana [24]
The trapezoid was translated Right 6 ,down 5
3 0
2 years ago
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