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2 years ago

!! HELP PLEASE!!

Mathematics

2 answers:

olasank [31]2 years ago

7 0

Here

a=22
b=21
c=16

Apply law of cosines

$\ \ \sf\longmapsto cosB=\dfrac{a^2+b^2+c^2}{2ac}$

$\ \ \sf\longmapsto cosB=\dfrac{22^2+21^2+16^2}{2(22)(16)}$

$\ \ \sf\longmapsto cosB=\dfrac{484+441+256}{704}$

$\ \ \sf\longmapsto cosB=\dfrac{1181}{704}$

$\ \ \sf\longmapsto cosB=0.42$

$\ \ \sf\longmapsto B=cos^{-1}(0.42)$

$\ \ \sf\longmapsto B=64.8°$

NARA [144]2 years ago

3 0

Answer:

64.86°

Step-by-step explanation:

<u>Use the law of cosines:</u>

cos ∠B = (a² + c² - b²) / (2ac)
cos ∠B = (16² + 22² - 21²) / (2*16*22)
cos ∠B = 0.4247
m∠B = arccos 0.4247
m∠B = 64.86° (rounded to the nearest hundredths)

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Solution to the problem

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$Y \sim Binom(n=5, p=0.05)$

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