Question

!! HELP PLEASE!!

Answer 1

Here

• a=22
• b=21
• c=16

Apply law of cosines

$\ \ \sf\longmapsto cosB=\dfrac{a^2+b^2+c^2}{2ac}$

$\ \ \sf\longmapsto cosB=\dfrac{22^2+21^2+16^2}{2(22)(16)}$

$\ \ \sf\longmapsto cosB=\dfrac{484+441+256}{704}$

$\ \ \sf\longmapsto cosB=\dfrac{1181}{704}$

$\ \ \sf\longmapsto cosB=0.42$

$\ \ \sf\longmapsto B=cos^{-1}(0.42)$

$\ \ \sf\longmapsto B=64.8°$

Answer 2

Answer:

• 64.86°

Step-by-step explanation:

Use the law of cosines:

• cos ∠B = (a² + c² - b²) / (2ac)
• cos ∠B = (16² + 22² - 21²) / (2*16*22)
• cos ∠B = 0.4247
• m∠B = arccos 0.4247
• m∠B = 64.86° (rounded to the nearest hundredths)