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REY [17]
2 years ago
6

Hello everyone, i am very confused by this question:

Mathematics
1 answer:
Lesechka [4]2 years ago
8 0

Answer:

Read the explanation down

Step-by-step explanation:

This is a linear equation, because the equation does not have any exponents. Graph it by putting the equation into either slope-intercept form y=mx+b or point-slope form y−y1=m(x−x1).

Isolate y by first adding 6x to each side:

9y=6x−18

Divide each side by 9:

y=23x−2

Now graph the line y=23x−2 by first plotting the y intercept at (0,−2), then connecting points with a slope of 23.

graph{2/3x-2 [-10, 10, -5, 5]}

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​ What are the zeros of the function?​ f(x)=x2+17x+72
Semmy [17]
In order to find zeroes of a function, we will probably want to use our quadratic formula.

-b±√b^2-4(a)(c)/2a 

If we know our values, we can plug it in. 

Our values:

A=1 (Since there is no number in front of x, it is an assumed 1)
B=17
C=72

Now, We can plug it into our formula.

BE SURE TO PUT PARENTHESIS AROUND ALL TERMS!

-(17)±√(17)^2-4(1)(72)/2(1)

Now we can type it into a calculator! 

When we plug it into the formula. It gives us two real solutions (or zeroes) which are represented as:

-8 & -9.

4 0
3 years ago
How do you prove theorems behind two parallel lines cut by a transversal?
LenaWriter [7]
The way to do it can be explained like this:
Say AB and CD are the two parallel lines cut by a transversal at E and F respectively.
 Then the pairs of alternate interior angles are:
Angle(AEF) and Angle(DFE)
Angle(CFE) and Angle(BEF)
Now lets prove if this is true:
<span>Angle(CFE) +Angle(DFE) = 180
(linear pair)
Also
Angle(CFE) +Angle(AEF) = 180
(Corresponding angles)
</span><span>Equate the above results:
Angle(CFE) +Angle(DFE) = Angle(CFE) +Angle(AEF)
</span><span>Angle(DFE) = Angle(AEF)
</span>Happens the same with
<span>Angle(CFE) = Angle(BEF)
</span>Hope this is very useful for you

5 0
3 years ago
Do you like unspeakable keep answers pg plz
suter [353]

Answer:

I like unspeakable! :))

8 0
3 years ago
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zavuch27 [327]

Answer:

0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

Step-by-step explanation:

Given the data in the question;

sample size n = 28

slope of the least squares regression line of y on x or sample estimate = 0.0623

standard error = 0.0224

95% confidence interval

level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05

degree of freedom df = n - 2 = 28 - 2 = 26

∴ the equation will be;

⇒ sample estimate ± ( t-test) ( standard error )

⇒ sample estimate ± ( t_{\alpha /2, df) ( standard error )

⇒ sample estimate ± ( t_{0.05 /2, 26) ( standard error )

⇒ sample estimate ± ( t_{0.025, 26) ( standard error )

{ from t table; ( t_{0.025, 26) = 2.055529 = 2.056

so we substitute

⇒ 0.0623 ± ( 2.056 )( 0.0224 )

Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

5 0
3 years ago
Reena bought a mobile phone for 16,240 that included a GST of 12%. Find the price of the mobile phone before the GST was added.​
NNADVOKAT [17]

Answer: 14500

Step-by-step explanation:

Let the price of the mobile phone before the GST was added be represented by x.

Therefore,

x + (12% × x) = 16240

x + 0.12x = 16240

1.12x = 16240

x = 16240/1.12

x = 14500

The price of the mobile phone before the GST was added was 14500

4 0
3 years ago
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