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2 years ago

Hey guys can u pls help me.

Mathematics

2 answers:

nadya68 [22]2 years ago

4 0

Answer:

It's b

it's kinda hard to explain but it ends up showing .7x.5 on the example, so your answer is B

liubo4ka [24]2 years ago

4 0

Answer:

answer b also i just want points lol

Step-by-step explanation:

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Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula? Qu

Likurg_2 [28]

Answer:

a = 1

b = -1

c = -2

Step-by-step explanation:

We reorder the equation in such way that let us see the usual

ax² + bx + c = 0

Then the original quation is:

-2 = - x + x² - 4 ⇒ 0 = 2 - x + x² - 4 ⇒ x² - x - 2 = 0

Now we are able by simply inspection to identify a, b . c comparing our equation with the general equation so :

a = 1

b = -1

c = -2

5 0

3 years ago

Read 2 more answers

2 fractions between 3/5 and 4/5

Tasya [4]

Convert the fractions to decimals:

3/5=0.6
4/5=0.8

You have to find 2 fractions between these 2 numbers. You could pick anything.

7/10= 0.7 = less than 0.8 but greater than 0.6

75/100=0.75 = less than 0.8 but greater than 0.6

Hope this helps

3 0

3 years ago

Which of the following is the graph of y=sqr root -x-3

Elan Coil [88]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

$y=\sqrt{-x-3}$

we know that

The radicand must be greater than or equal to zero

$(-x-3)\geq 0$

solve for x

Adds 3 both sides

$-x\geq 0+3$

$-x\geq 3$

Multiply by -1 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x\leq -3$

The domain of the function is the interval (-∞,-3]

For x=-3 ---> the value of y=0

The range is the interval {0,∞)

therefore

The graph in the attached figure

3 0

3 years ago

I need help with this one please..

KiRa [710]

I think it's 60 I'm NOT sure. I just multiplied those three numbers

4 0

3 years ago

HELP ITS TIMEDDD !!!!

lidiya [134]

Answer:

SAS.........,..,....

8 0

3 years ago

Hey guys can u pls help me.​

Hey guys can u pls help me.